Base | Representation |
---|---|
bin | 11111111001110011110000… |
… | …010010100001010001011000 |
3 | 200101210200212010120212211100 |
4 | 133321303300102201101120 |
5 | 121342333010342344230 |
6 | 1214230241543031400 |
7 | 41361131506112016 |
oct | 3771636022412130 |
9 | 611720763525740 |
10 | 140312023012440 |
11 | 40786aa4077764 |
12 | 138a14b073b560 |
13 | 603a4a03a0446 |
14 | 26911d111b8b6 |
15 | 1134c87464660 |
hex | 7f9cf04a1458 |
140312023012440 has 192 divisors, whose sum is σ = 456540817168800. Its totient is φ = 37373332525056.
The previous prime is 140312023012429. The next prime is 140312023012487. The reversal of 140312023012440 is 44210320213041.
140312023012440 is a `hidden beast` number, since 1 + 4 + 0 + 3 + 1 + 202 + 3 + 0 + 12 + 440 = 666.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 2337841312 + ... + 2337901328.
Almost surely, 2140312023012440 is an apocalyptic number.
140312023012440 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 140312023012440, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (228270408584400).
140312023012440 is an abundant number, since it is smaller than the sum of its proper divisors (316228794156360).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
140312023012440 is a wasteful number, since it uses less digits than its factorization.
140312023012440 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 67426 (or 67419 counting only the distinct ones).
The product of its (nonzero) digits is 4608, while the sum is 27.
Adding to 140312023012440 its reverse (44210320213041), we get a palindrome (184522343225481).
The spelling of 140312023012440 in words is "one hundred forty trillion, three hundred twelve billion, twenty-three million, twelve thousand, four hundred forty".
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