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140312351353 is a prime number
BaseRepresentation
bin1000001010101101000…
…1001001001001111001
3111102011121102222020211
42002223101021021321
54244324430220403
6144243020351121
713065033210436
oct2025321111171
9442147388224
10140312351353
1154562734359
122323a3a54a1
13103014c5995
146b10cd8b8d
1539b337006d
hex20ab449279

140312351353 has 2 divisors, whose sum is σ = 140312351354. Its totient is φ = 140312351352.

The previous prime is 140312351293. The next prime is 140312351447. The reversal of 140312351353 is 353153213041.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 114702110329 + 25610241024 = 338677^2 + 160032^2 .

It is a cyclic number.

It is not a de Polignac number, because 140312351353 - 213 = 140312343161 is a prime.

It is not a weakly prime, because it can be changed into another prime (140312951353) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70156175676 + 70156175677.

It is an arithmetic number, because the mean of its divisors is an integer number (70156175677).

Almost surely, 2140312351353 is an apocalyptic number.

It is an amenable number.

140312351353 is a deficient number, since it is larger than the sum of its proper divisors (1).

140312351353 is an equidigital number, since it uses as much as digits as its factorization.

140312351353 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 16200, while the sum is 31.

Adding to 140312351353 its reverse (353153213041), we get a palindrome (493465564394).

The spelling of 140312351353 in words is "one hundred forty billion, three hundred twelve million, three hundred fifty-one thousand, three hundred fifty-three".