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14031402339967 is a prime number
BaseRepresentation
bin1100110000101111000011…
…0000001000111001111111
31211200101111112222002220221
43030023300300020321333
53314342302444334332
645501534240122211
72645510142006115
oct314136060107177
954611445862827
1014031402339967
11451a758906471
1216a7468306367
137aa203a068bc
143671a2c37ab5
15194ec7bd0297
hexcc2f0c08e7f

14031402339967 has 2 divisors, whose sum is σ = 14031402339968. Its totient is φ = 14031402339966.

The previous prime is 14031402339959. The next prime is 14031402340031. The reversal of 14031402339967 is 76993320413041.

14031402339967 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 14031402339967 - 23 = 14031402339959 is a prime.

It is a super-2 number, since 2×140314023399672 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14031402334967) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7015701169983 + 7015701169984.

It is an arithmetic number, because the mean of its divisors is an integer number (7015701169984).

Almost surely, 214031402339967 is an apocalyptic number.

14031402339967 is a deficient number, since it is larger than the sum of its proper divisors (1).

14031402339967 is an equidigital number, since it uses as much as digits as its factorization.

14031402339967 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2939328, while the sum is 52.

The spelling of 14031402339967 in words is "fourteen trillion, thirty-one billion, four hundred two million, three hundred thirty-nine thousand, nine hundred sixty-seven".