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14031404423 is a prime number
BaseRepresentation
bin11010001000101011…
…00011110110000111
31100012212120012100022
431010111203312013
5212214014420143
610240153405355
71004465653421
oct150425436607
940185505308
1014031404423
115a503a8903
12287710985b
131427c8618a
1497172d811
15571c88268
hex344563d87

14031404423 has 2 divisors, whose sum is σ = 14031404424. Its totient is φ = 14031404422.

The previous prime is 14031404389. The next prime is 14031404437. The reversal of 14031404423 is 32440413041.

14031404423 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is an emirp because it is prime and its reverse (32440413041) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14031404423 - 216 = 14031338887 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 14031404392 and 14031404401.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14031424423) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7015702211 + 7015702212.

It is an arithmetic number, because the mean of its divisors is an integer number (7015702212).

Almost surely, 214031404423 is an apocalyptic number.

14031404423 is a deficient number, since it is larger than the sum of its proper divisors (1).

14031404423 is an equidigital number, since it uses as much as digits as its factorization.

14031404423 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4608, while the sum is 26.

Adding to 14031404423 its reverse (32440413041), we get a palindrome (46471817464).

The spelling of 14031404423 in words is "fourteen billion, thirty-one million, four hundred four thousand, four hundred twenty-three".