Base | Representation |
---|---|
bin | 1100110000110001011011… |
… | …0100111110011110000111 |
3 | 1211200110011001222121210002 |
4 | 3030030112310332132013 |
5 | 3314400110013022101 |
6 | 45502121455551515 |
7 | 2645532026514134 |
oct | 314142664763607 |
9 | 54613131877702 |
10 | 14032041142151 |
11 | 451aa56456a5a |
12 | 16a760622b59b |
13 | 7aa2a6169a66 |
14 | 367223a0158b |
15 | 195013d14d6b |
hex | cc316d3e787 |
14032041142151 has 2 divisors, whose sum is σ = 14032041142152. Its totient is φ = 14032041142150.
The previous prime is 14032041142103. The next prime is 14032041142201. The reversal of 14032041142151 is 15124114023041.
It is a weak prime.
It is an emirp because it is prime and its reverse (15124114023041) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 14032041142151 - 210 = 14032041141127 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14032041142451) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7016020571075 + 7016020571076.
It is an arithmetic number, because the mean of its divisors is an integer number (7016020571076).
Almost surely, 214032041142151 is an apocalyptic number.
14032041142151 is a deficient number, since it is larger than the sum of its proper divisors (1).
14032041142151 is an equidigital number, since it uses as much as digits as its factorization.
14032041142151 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3840, while the sum is 29.
Adding to 14032041142151 its reverse (15124114023041), we get a palindrome (29156155165192).
The spelling of 14032041142151 in words is "fourteen trillion, thirty-two billion, forty-one million, one hundred forty-two thousand, one hundred fifty-one".
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