140330012110031 has 2 divisors, whose sum is σ = 140330012110032. Its totient is φ = 140330012110030.

The previous prime is 140330012109979. The next prime is 140330012110049. The reversal of 140330012110031 is 130011210033041.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-140330012110031 is a prime.

It is a super-2 number, since 2×140330012110031² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 140330012109985 and 140330012110012.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (140330012110081) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70165006055015 + 70165006055016.

It is an arithmetic number, because the mean of its divisors is an integer number (70165006055016).

Almost surely, 2^{140330012110031} is an apocalyptic number.

140330012110031 is a deficient number, since it is larger than the sum of its proper divisors (1).

140330012110031 is an equidigital number, since it uses as much as digits as its factorization.

140330012110031 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 216, while the sum is 20.

Adding to 140330012110031 its reverse (130011210033041), we get a palindrome (270341222143072).

The spelling of 140330012110031 in words is "one hundred forty trillion, three hundred thirty billion, twelve million, one hundred ten thousand, thirty-one".