Base | Representation |
---|---|
bin | 1100110000110101011101… |
… | …0000001010111101011111 |
3 | 1211200112221101211112212121 |
4 | 3030031113100022331133 |
5 | 3314404313213404043 |
6 | 45502421030443411 |
7 | 2645600562666151 |
oct | 314152720127537 |
9 | 54615841745777 |
10 | 14033122013023 |
11 | 4520460596273 |
12 | 16a7868203567 |
13 | 7aa419080819 |
14 | 3672c73a0ad1 |
15 | 195078b6cded |
hex | cc35740af5f |
14033122013023 has 8 divisors (see below), whose sum is σ = 14184893115792. Its totient is φ = 13881495803136.
The previous prime is 14033122013011. The next prime is 14033122013069. The reversal of 14033122013023 is 32031022133041.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 14033122013023 - 217 = 14033121881951 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14033122013623) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 36028465 + ... + 36415882.
It is an arithmetic number, because the mean of its divisors is an integer number (1773111639474).
Almost surely, 214033122013023 is an apocalyptic number.
14033122013023 is a deficient number, since it is larger than the sum of its proper divisors (151771102769).
14033122013023 is an equidigital number, since it uses as much as digits as its factorization.
14033122013023 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 72446441.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 14033122013023 its reverse (32031022133041), we get a palindrome (46064144146064).
The spelling of 14033122013023 in words is "fourteen trillion, thirty-three billion, one hundred twenty-two million, thirteen thousand, twenty-three".
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