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14033341212134 = 28822897952803
BaseRepresentation
bin1100110000110110010001…
…0100010110010111100110
31211200120111200022000112012
43030031210110112113212
53314410240322242014
645502454500554222
72645606164105466
oct314154424262746
954616450260465
1014033341212134
1145205632a1862
1216a79096b2972
137aa4525ca83a
1436730853dba6
1519508d01ac3e
hexcc3645165e6

14033341212134 has 8 divisors (see below), whose sum is σ = 21050038323480. Its totient is φ = 7016661770976.

The previous prime is 14033341212133. The next prime is 14033341212173. The reversal of 14033341212134 is 43121214333041.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a self number, because there is not a number n which added to its sum of digits gives 14033341212134.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14033341212133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2211824 + ... + 5740979.

It is an arithmetic number, because the mean of its divisors is an integer number (2631254790435).

Almost surely, 214033341212134 is an apocalyptic number.

14033341212134 is a deficient number, since it is larger than the sum of its proper divisors (7016697111346).

14033341212134 is an equidigital number, since it uses as much as digits as its factorization.

14033341212134 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8835094.

The product of its (nonzero) digits is 20736, while the sum is 32.

Adding to 14033341212134 its reverse (43121214333041), we get a palindrome (57154555545175).

The spelling of 14033341212134 in words is "fourteen trillion, thirty-three billion, three hundred forty-one million, two hundred twelve thousand, one hundred thirty-four".

Divisors: 1 2 882289 1764578 7952803 15905606 7016670606067 14033341212134