1403334331213 has 2 divisors, whose sum is σ = 1403334331214. Its totient is φ = 1403334331212.

The previous prime is 1403334331199. The next prime is 1403334331247. The reversal of 1403334331213 is 3121334333041.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1299264861609 + 104069469604 = 1139853^2 + 322598^2 .

It is a cyclic number.

It is not a de Polignac number, because 1403334331213 - 2¹⁷ = 1403334200141 is a prime.

It is a super-2 number, since 2×1403334331213² (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1403334331313) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 701667165606 + 701667165607.

It is an arithmetic number, because the mean of its divisors is an integer number (701667165607).

Almost surely, 2^{1403334331213} is an apocalyptic number.

It is an amenable number.

1403334331213 is a deficient number, since it is larger than the sum of its proper divisors (1).

1403334331213 is an equidigital number, since it uses as much as digits as its factorization.

1403334331213 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 23328, while the sum is 31.

Adding to 1403334331213 its reverse (3121334333041), we get a palindrome (4524668664254).

The spelling of 1403334331213 in words is "one trillion, four hundred three billion, three hundred thirty-four million, three hundred thirty-one thousand, two hundred thirteen".