Base | Representation |
---|---|
bin | 1100110000111000101110… |
… | …1010011100001001001111 |
3 | 1211200122012200101200120122 |
4 | 3030032023222130021033 |
5 | 3314413113314030013 |
6 | 45503044201135155 |
7 | 2645631430636031 |
oct | 314161352341117 |
9 | 54618180350518 |
10 | 14034001314383 |
11 | 4520871970406 |
12 | 16a7a7278a4bb |
13 | 7aa5292aaa9b |
14 | 36736c08dc51 |
15 | 1950cae5ba08 |
hex | cc38ba9c24f |
14034001314383 has 2 divisors, whose sum is σ = 14034001314384. Its totient is φ = 14034001314382.
The previous prime is 14034001314341. The next prime is 14034001314391. The reversal of 14034001314383 is 38341310043041.
14034001314383 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 14034001314383 - 220 = 14034000265807 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14034001314313) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7017000657191 + 7017000657192.
It is an arithmetic number, because the mean of its divisors is an integer number (7017000657192).
Almost surely, 214034001314383 is an apocalyptic number.
14034001314383 is a deficient number, since it is larger than the sum of its proper divisors (1).
14034001314383 is an equidigital number, since it uses as much as digits as its factorization.
14034001314383 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 41472, while the sum is 35.
The spelling of 14034001314383 in words is "fourteen trillion, thirty-four billion, one million, three hundred fourteen thousand, three hundred eighty-three".
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