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14034203333323 is a prime number
BaseRepresentation
bin1100110000111001011110…
…1101000101001011001011
31211200122201202112022110121
43030032113231011023023
53314414022023131243
645503120215124111
72645636433032365
oct314162755051313
954618652468417
1014034203333323
114520965a02208
1216a7b0a373637
137aa55c0c1014
1436738ac39d35
151950dda641ed
hexcc397b452cb

14034203333323 has 2 divisors, whose sum is σ = 14034203333324. Its totient is φ = 14034203333322.

The previous prime is 14034203333309. The next prime is 14034203333389. The reversal of 14034203333323 is 32333330243041.

It is a weak prime.

It is an emirp because it is prime and its reverse (32333330243041) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14034203333323 - 229 = 14033666462411 is a prime.

It is a super-3 number, since 3×140342033333233 (a number of 40 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (14034203334323) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7017101666661 + 7017101666662.

It is an arithmetic number, because the mean of its divisors is an integer number (7017101666662).

Almost surely, 214034203333323 is an apocalyptic number.

14034203333323 is a deficient number, since it is larger than the sum of its proper divisors (1).

14034203333323 is an equidigital number, since it uses as much as digits as its factorization.

14034203333323 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 139968, while the sum is 34.

Adding to 14034203333323 its reverse (32333330243041), we get a palindrome (46367533576364).

The spelling of 14034203333323 in words is "fourteen trillion, thirty-four billion, two hundred three million, three hundred thirty-three thousand, three hundred twenty-three".