Base | Representation |
---|---|
bin | 1100110000111100111010… |
… | …0001110001010100111011 |
3 | 1211200202002212021002011121 |
4 | 3030033032201301110323 |
5 | 3314422413004142243 |
6 | 45503351353210111 |
7 | 2646001302041512 |
oct | 314171641612473 |
9 | 54622085232147 |
10 | 14035123115323 |
11 | 4521298116022 |
12 | 16a8126400937 |
13 | 7aa67782281b |
14 | 367437065679 |
15 | 19514469c1ed |
hex | cc3ce87153b |
14035123115323 has 2 divisors, whose sum is σ = 14035123115324. Its totient is φ = 14035123115322.
The previous prime is 14035123115311. The next prime is 14035123115333. The reversal of 14035123115323 is 32351132153041.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14035123115323 is a prime.
It is not a weakly prime, because it can be changed into another prime (14035123115333) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7017561557661 + 7017561557662.
It is an arithmetic number, because the mean of its divisors is an integer number (7017561557662).
Almost surely, 214035123115323 is an apocalyptic number.
14035123115323 is a deficient number, since it is larger than the sum of its proper divisors (1).
14035123115323 is an equidigital number, since it uses as much as digits as its factorization.
14035123115323 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 32400, while the sum is 34.
Adding to 14035123115323 its reverse (32351132153041), we get a palindrome (46386255268364).
The spelling of 14035123115323 in words is "fourteen trillion, thirty-five billion, one hundred twenty-three million, one hundred fifteen thousand, three hundred twenty-three".
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