Base | Representation |
---|---|
bin | 1100110000111100111100… |
… | …0001111010111001100011 |
3 | 1211200202010110010020221221 |
4 | 3030033033001322321203 |
5 | 3314422422133340024 |
6 | 45503352253555511 |
7 | 2646001433502430 |
oct | 314171701727143 |
9 | 54622113106857 |
10 | 14035131543139 |
11 | 45212a1951a63 |
12 | 16a81291a5b97 |
13 | 7aa6794b38b5 |
14 | 36743821ab87 |
15 | 1951452b43e4 |
hex | cc3cf07ae63 |
14035131543139 has 4 divisors (see below), whose sum is σ = 16040150335024. Its totient is φ = 12030112751256.
The previous prime is 14035131543127. The next prime is 14035131543161. The reversal of 14035131543139 is 93134513153041.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 14035131543139 - 213 = 14035131534947 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 14035131543095 and 14035131543104.
It is not an unprimeable number, because it can be changed into a prime (14035131243139) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1002509395932 + ... + 1002509395945.
It is an arithmetic number, because the mean of its divisors is an integer number (4010037583756).
Almost surely, 214035131543139 is an apocalyptic number.
14035131543139 is a deficient number, since it is larger than the sum of its proper divisors (2005018791885).
14035131543139 is an equidigital number, since it uses as much as digits as its factorization.
14035131543139 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2005018791884.
The product of its (nonzero) digits is 291600, while the sum is 43.
The spelling of 14035131543139 in words is "fourteen trillion, thirty-five billion, one hundred thirty-one million, five hundred forty-three thousand, one hundred thirty-nine".
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