Base | Representation |
---|---|
bin | 1100110000111100111100… |
… | …0001111010111001010111 |
3 | 1211200202010110010020221111 |
4 | 3030033033001322321113 |
5 | 3314422422133340002 |
6 | 45503352253555451 |
7 | 2646001433502412 |
oct | 314171701727127 |
9 | 54622113106844 |
10 | 14035131543127 |
11 | 45212a1951a52 |
12 | 16a81291a5b87 |
13 | 7aa6794b38a6 |
14 | 36743821ab79 |
15 | 1951452b43d7 |
hex | cc3cf07ae57 |
14035131543127 has 2 divisors, whose sum is σ = 14035131543128. Its totient is φ = 14035131543126.
The previous prime is 14035131543089. The next prime is 14035131543161. The reversal of 14035131543127 is 72134513153041.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14035131543127 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 14035131543127.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14035131543187) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7017565771563 + 7017565771564.
It is an arithmetic number, because the mean of its divisors is an integer number (7017565771564).
Almost surely, 214035131543127 is an apocalyptic number.
14035131543127 is a deficient number, since it is larger than the sum of its proper divisors (1).
14035131543127 is an equidigital number, since it uses as much as digits as its factorization.
14035131543127 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 151200, while the sum is 40.
Adding to 14035131543127 its reverse (72134513153041), we get a palindrome (86169644696168).
The spelling of 14035131543127 in words is "fourteen trillion, thirty-five billion, one hundred thirty-one million, five hundred forty-three thousand, one hundred twenty-seven".
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