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14035131543161 is a prime number
BaseRepresentation
bin1100110000111100111100…
…0001111010111001111001
31211200202010110010020222202
43030033033001322321321
53314422422133340121
645503352253555545
72646001433502461
oct314171701727171
954622113106882
1014035131543161
1145212a1951a83
1216a81291a5bb5
137aa6794b3901
1436743821aba1
151951452b440b
hexcc3cf07ae79

14035131543161 has 2 divisors, whose sum is σ = 14035131543162. Its totient is φ = 14035131543160.

The previous prime is 14035131543127. The next prime is 14035131543187. The reversal of 14035131543161 is 16134513153041.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7837446607936 + 6197684935225 = 2799544^2 + 2489515^2 .

It is a cyclic number.

It is not a de Polignac number, because 14035131543161 - 214 = 14035131526777 is a prime.

It is not a weakly prime, because it can be changed into another prime (14035131543661) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7017565771580 + 7017565771581.

It is an arithmetic number, because the mean of its divisors is an integer number (7017565771581).

Almost surely, 214035131543161 is an apocalyptic number.

It is an amenable number.

14035131543161 is a deficient number, since it is larger than the sum of its proper divisors (1).

14035131543161 is an equidigital number, since it uses as much as digits as its factorization.

14035131543161 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 64800, while the sum is 38.

The spelling of 14035131543161 in words is "fourteen trillion, thirty-five billion, one hundred thirty-one million, five hundred forty-three thousand, one hundred sixty-one".