14035801331 has 2 divisors, whose sum is σ = 14035801332. Its totient is φ = 14035801330.

The previous prime is 14035801327. The next prime is 14035801333. The reversal of 14035801331 is 13310853041.

14035801331 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 14035801331 - 2² = 14035801327 is a prime.

It is a super-2 number, since 2×14035801331² (a number of 21 digits) contains 22 as substring.

Together with 14035801333, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 14035801294 and 14035801303.

It is not a weakly prime, because it can be changed into another prime (14035801333) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7017900665 + 7017900666.

It is an arithmetic number, because the mean of its divisors is an integer number (7017900666).

Almost surely, 2^14035801331 is an apocalyptic number.

14035801331 is a deficient number, since it is larger than the sum of its proper divisors (1).

14035801331 is an equidigital number, since it uses as much as digits as its factorization.

14035801331 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4320, while the sum is 29.

The spelling of 14035801331 in words is "fourteen billion, thirty-five million, eight hundred one thousand, three hundred thirty-one".