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14040052241153 is a prime number
BaseRepresentation
bin1100110001001111010001…
…0100111001001100000001
31211201012211101021121122112
43030103310110321030001
53320013011333204103
645505524433345105
72646234403651661
oct314236424711401
954635741247575
1014040052241153
114523397515234
1216a9081108195
137aac81a97a23
143677839581a1
151953322a3cd8
hexcc4f4539301

14040052241153 has 2 divisors, whose sum is σ = 14040052241154. Its totient is φ = 14040052241152.

The previous prime is 14040052241071. The next prime is 14040052241209. The reversal of 14040052241153 is 35114225004041.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13946699382784 + 93352858369 = 3734528^2 + 305537^2 .

It is an emirp because it is prime and its reverse (35114225004041) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14040052241153 - 210 = 14040052240129 is a prime.

It is not a weakly prime, because it can be changed into another prime (14040052241353) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7020026120576 + 7020026120577.

It is an arithmetic number, because the mean of its divisors is an integer number (7020026120577).

Almost surely, 214040052241153 is an apocalyptic number.

It is an amenable number.

14040052241153 is a deficient number, since it is larger than the sum of its proper divisors (1).

14040052241153 is an equidigital number, since it uses as much as digits as its factorization.

14040052241153 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 19200, while the sum is 32.

Adding to 14040052241153 its reverse (35114225004041), we get a palindrome (49154277245194).

The spelling of 14040052241153 in words is "fourteen trillion, forty billion, fifty-two million, two hundred forty-one thousand, one hundred fifty-three".