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140401207 is a prime number
BaseRepresentation
bin10000101111001…
…01101000110111
3100210012010020201
420113211220313
5241420314312
621533141331
73323250652
oct1027455067
9323163221
10140401207
1172286561
123b02a847
132311ab4b
141490a899
15c4d5557
hex85e5a37

140401207 has 2 divisors, whose sum is σ = 140401208. Its totient is φ = 140401206.

The previous prime is 140401189. The next prime is 140401213. The reversal of 140401207 is 702104041.

It is a strong prime.

It is an emirp because it is prime and its reverse (702104041) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 140401207 - 211 = 140399159 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (140401237) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70200603 + 70200604.

It is an arithmetic number, because the mean of its divisors is an integer number (70200604).

Almost surely, 2140401207 is an apocalyptic number.

140401207 is a deficient number, since it is larger than the sum of its proper divisors (1).

140401207 is an equidigital number, since it uses as much as digits as its factorization.

140401207 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 224, while the sum is 19.

The square root of 140401207 is about 11849.1015271201. The cubic root of 140401207 is about 519.7449525886.

Adding to 140401207 its reverse (702104041), we get a palindrome (842505248).

It can be divided in two parts, 140401 and 207, that added together give a cube (140608 = 523).

The spelling of 140401207 in words is "one hundred forty million, four hundred one thousand, two hundred seven".