Base | Representation |
---|---|
bin | 1100110001001111100011… |
… | …1101100110001010110111 |
3 | 1211201020000210122012012102 |
4 | 3030103320331212022313 |
5 | 3320013141241120043 |
6 | 45505540252412315 |
7 | 2646236340034352 |
oct | 314237075461267 |
9 | 54636023565172 |
10 | 14040130020023 |
11 | 4523427409698 |
12 | 16a90a317709b |
13 | 7aac94c2b123 |
14 | 367790003299 |
15 | 1953390196b8 |
hex | cc4f8f662b7 |
14040130020023 has 2 divisors, whose sum is σ = 14040130020024. Its totient is φ = 14040130020022.
The previous prime is 14040130019983. The next prime is 14040130020067. The reversal of 14040130020023 is 32002003104041.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 14040130020023 - 214 = 14040130003639 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 14040130019977 and 14040130020004.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14040130020073) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7020065010011 + 7020065010012.
It is an arithmetic number, because the mean of its divisors is an integer number (7020065010012).
Almost surely, 214040130020023 is an apocalyptic number.
14040130020023 is a deficient number, since it is larger than the sum of its proper divisors (1).
14040130020023 is an equidigital number, since it uses as much as digits as its factorization.
14040130020023 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 576, while the sum is 20.
Adding to 14040130020023 its reverse (32002003104041), we get a palindrome (46042133124064).
The spelling of 14040130020023 in words is "fourteen trillion, forty billion, one hundred thirty million, twenty thousand, twenty-three".
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