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1404020124233 is a prime number
BaseRepresentation
bin10100011011100110000…
…111101110101001001001
311222020000120120021011222
4110123212013232221021
5141000413122433413
62552555315531425
7203302633100606
oct24334607565111
94866016507158
101404020124233
114a1494837111
121a81375b9b75
13a25247533cc
144bd524bb6ad
15267c605cb08
hex146e61eea49

1404020124233 has 2 divisors, whose sum is σ = 1404020124234. Its totient is φ = 1404020124232.

The previous prime is 1404020124137. The next prime is 1404020124259. The reversal of 1404020124233 is 3324210204041.

It is an a-pointer prime, because the next prime (1404020124259) can be obtained adding 1404020124233 to its sum of digits (26).

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 957524875024 + 446495249209 = 978532^2 + 668203^2 .

It is a cyclic number.

It is not a de Polignac number, because 1404020124233 - 212 = 1404020120137 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (1404020124293) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 702010062116 + 702010062117.

It is an arithmetic number, because the mean of its divisors is an integer number (702010062117).

Almost surely, 21404020124233 is an apocalyptic number.

It is an amenable number.

1404020124233 is a deficient number, since it is larger than the sum of its proper divisors (1).

1404020124233 is an equidigital number, since it uses as much as digits as its factorization.

1404020124233 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4608, while the sum is 26.

Adding to 1404020124233 its reverse (3324210204041), we get a palindrome (4728230328274).

The spelling of 1404020124233 in words is "one trillion, four hundred four billion, twenty million, one hundred twenty-four thousand, two hundred thirty-three".