1404032220113 has 2 divisors, whose sum is σ = 1404032220114. Its totient is φ = 1404032220112.

The previous prime is 1404032220077. The next prime is 1404032220119. The reversal of 1404032220113 is 3110222304041.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1108457325889 + 295574894224 = 1052833^2 + 543668^2 .

It is a cyclic number.

It is not a de Polignac number, because 1404032220113 - 2¹⁰ = 1404032219089 is a prime.

It is a super-3 number, since 3×1404032220113³ (a number of 37 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (1404032220119) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 702016110056 + 702016110057.

It is an arithmetic number, because the mean of its divisors is an integer number (702016110057).

Almost surely, 2^{1404032220113} is an apocalyptic number.

It is an amenable number.

1404032220113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1404032220113 is an equidigital number, since it uses as much as digits as its factorization.

1404032220113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 1404032220113 its reverse (3110222304041), we get a palindrome (4514254524154).

The spelling of 1404032220113 in words is "one trillion, four hundred four billion, thirty-two million, two hundred twenty thousand, one hundred thirteen".