Base | Representation |
---|---|
bin | 10100011011100110110… |
… | …101110111101111010111 |
3 | 11222020001102022210121202 |
4 | 110123212311313233113 |
5 | 141000424222020434 |
6 | 2553000431103115 |
7 | 203303140646564 |
oct | 24334665675727 |
9 | 4866042283552 |
10 | 1404032220119 |
11 | 4a14a0648a11 |
12 | 1a813b671a9b |
13 | a25270c9c39 |
14 | 4bd53d4986b |
15 | 267c714ba7e |
hex | 146e6d77bd7 |
1404032220119 has 2 divisors, whose sum is σ = 1404032220120. Its totient is φ = 1404032220118.
The previous prime is 1404032220113. The next prime is 1404032220127. The reversal of 1404032220119 is 9110222304041.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1404032220119 is a prime.
It is a super-3 number, since 3×14040322201193 (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Sophie Germain prime.
It is a junction number, because it is equal to n+sod(n) for n = 1404032220091 and 1404032220100.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1404032220113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 702016110059 + 702016110060.
It is an arithmetic number, because the mean of its divisors is an integer number (702016110060).
Almost surely, 21404032220119 is an apocalyptic number.
1404032220119 is a deficient number, since it is larger than the sum of its proper divisors (1).
1404032220119 is an equidigital number, since it uses as much as digits as its factorization.
1404032220119 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3456, while the sum is 29.
The spelling of 1404032220119 in words is "one trillion, four hundred four billion, thirty-two million, two hundred twenty thousand, one hundred nineteen".
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