14040413 has 2 divisors, whose sum is σ = 14040414. Its totient is φ = 14040412.

The previous prime is 14040391. The next prime is 14040421. The reversal of 14040413 is 31404041.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12687844 + 1352569 = 3562^2 + 1163^2 .

It is a cyclic number.

It is not a de Polignac number, because 14040413 - 2⁶ = 14040349 is a prime.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 14040391 and 14040400.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14040443) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7020206 + 7020207.

It is an arithmetic number, because the mean of its divisors is an integer number (7020207).

Almost surely, 2^14040413 is an apocalyptic number.

It is an amenable number.

14040413 is a deficient number, since it is larger than the sum of its proper divisors (1).

14040413 is an equidigital number, since it uses as much as digits as its factorization.

14040413 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 192, while the sum is 17.

The square root of 14040413 is about 3747.0539094067. The cubic root of 14040413 is about 241.2459109619.

Adding to 14040413 its reverse (31404041), we get a palindrome (45444454).

The spelling of 14040413 in words is "fourteen million, forty thousand, four hundred thirteen".