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140405651 is a prime number
BaseRepresentation
bin10000101111001…
…10101110010011
3100210012100100022
420113212232103
5241420440101
621533214055
73323266631
oct1027465623
9323170308
10140405651
1172289931
123b03132b
132311cb89
141490c351
15c4d6a1b
hex85e6b93

140405651 has 2 divisors, whose sum is σ = 140405652. Its totient is φ = 140405650.

The previous prime is 140405641. The next prime is 140405653. The reversal of 140405651 is 156504041.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 140405651 - 214 = 140389267 is a prime.

Together with 140405653, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 140405651.

It is not a weakly prime, because it can be changed into another prime (140405653) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70202825 + 70202826.

It is an arithmetic number, because the mean of its divisors is an integer number (70202826).

Almost surely, 2140405651 is an apocalyptic number.

140405651 is a deficient number, since it is larger than the sum of its proper divisors (1).

140405651 is an equidigital number, since it uses as much as digits as its factorization.

140405651 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2400, while the sum is 26.

The square root of 140405651 is about 11849.2890504030. The cubic root of 140405651 is about 519.7504362124.

Adding to 140405651 its reverse (156504041), we get a palindrome (296909692).

It can be divided in two parts, 14040 and 5651, that added together give a palindrome (19691).

The spelling of 140405651 in words is "one hundred forty million, four hundred five thousand, six hundred fifty-one".