Base | Representation |
---|---|
bin | 1100110001010011010000… |
… | …0101110000100100101111 |
3 | 1211201022120221020210012221 |
4 | 3030110310011300210233 |
5 | 3320022204213444120 |
6 | 45510222530340211 |
7 | 2646303043616506 |
oct | 314246405604457 |
9 | 54638527223187 |
10 | 14041122015535 |
11 | 452389636559a |
12 | 16a931b42a667 |
13 | 7ab0c25c4b14 |
14 | 367845a6983d |
15 | 1953961690aa |
hex | cc53417092f |
14041122015535 has 32 divisors (see below), whose sum is σ = 17851582187712. Its totient is φ = 10565564897280.
The previous prime is 14041122015533. The next prime is 14041122015581. The reversal of 14041122015535 is 53551022114041.
It is not a de Polignac number, because 14041122015535 - 21 = 14041122015533 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 14041122015535.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14041122015533) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1325003857 + ... + 1325014453.
It is an arithmetic number, because the mean of its divisors is an integer number (557861943366).
Almost surely, 214041122015535 is an apocalyptic number.
14041122015535 is a deficient number, since it is larger than the sum of its proper divisors (3810460172177).
14041122015535 is a wasteful number, since it uses less digits than its factorization.
14041122015535 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 18843.
The product of its (nonzero) digits is 24000, while the sum is 34.
Adding to 14041122015535 its reverse (53551022114041), we get a palindrome (67592144129576).
The spelling of 14041122015535 in words is "fourteen trillion, forty-one billion, one hundred twenty-two million, fifteen thousand, five hundred thirty-five".
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