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14042005414001 is a prime number
BaseRepresentation
bin1100110001010110100010…
…1111101010000001110001
31211201101212111112002002122
43030111220233222001301
53320031011341222001
645510450324524025
72646333661442315
oct314255057520161
954641774462078
1014042005414001
1145241a9a88974
1216a9527250615
137ab203627bc6
143678cb103b45
151953e89b6b1b
hexcc568bea071

14042005414001 has 2 divisors, whose sum is σ = 14042005414002. Its totient is φ = 14042005414000.

The previous prime is 14042005413979. The next prime is 14042005414027. The reversal of 14042005414001 is 10041450024041.

It is an a-pointer prime, because the next prime (14042005414027) can be obtained adding 14042005414001 to its sum of digits (26).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9024472613776 + 5017532800225 = 3004076^2 + 2239985^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14042005414001 is a prime.

It is not a weakly prime, because it can be changed into another prime (14042005414601) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7021002707000 + 7021002707001.

It is an arithmetic number, because the mean of its divisors is an integer number (7021002707001).

Almost surely, 214042005414001 is an apocalyptic number.

It is an amenable number.

14042005414001 is a deficient number, since it is larger than the sum of its proper divisors (1).

14042005414001 is an equidigital number, since it uses as much as digits as its factorization.

14042005414001 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2560, while the sum is 26.

Adding to 14042005414001 its reverse (10041450024041), we get a palindrome (24083455438042).

The spelling of 14042005414001 in words is "fourteen trillion, forty-two billion, five million, four hundred fourteen thousand, one".