Base | Representation |
---|---|
bin | 1100110001011010010011… |
… | …0001100101010110100111 |
3 | 1211201111110200121222211211 |
4 | 3030112210301211112213 |
5 | 3320040042203131403 |
6 | 45511134303212251 |
7 | 2646400641123103 |
oct | 314264461452647 |
9 | 54644420558754 |
10 | 14043012552103 |
11 | 4524676537707 |
12 | 16a97685a7087 |
13 | 7ab334194102 |
14 | 367984b8c903 |
15 | 19545710806d |
hex | cc5a4c655a7 |
14043012552103 has 2 divisors, whose sum is σ = 14043012552104. Its totient is φ = 14043012552102.
The previous prime is 14043012552091. The next prime is 14043012552167. The reversal of 14043012552103 is 30125521034041.
14043012552103 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 14043012552103 - 25 = 14043012552071 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14043012552203) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7021506276051 + 7021506276052.
It is an arithmetic number, because the mean of its divisors is an integer number (7021506276052).
Almost surely, 214043012552103 is an apocalyptic number.
14043012552103 is a deficient number, since it is larger than the sum of its proper divisors (1).
14043012552103 is an equidigital number, since it uses as much as digits as its factorization.
14043012552103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 14400, while the sum is 31.
Adding to 14043012552103 its reverse (30125521034041), we get a palindrome (44168533586144).
The spelling of 14043012552103 in words is "fourteen trillion, forty-three billion, twelve million, five hundred fifty-two thousand, one hundred three".
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