14043311332441 has 2 divisors, whose sum is σ = 14043311332442. Its totient is φ = 14043311332440.

The previous prime is 14043311332429. The next prime is 14043311332459. The reversal of 14043311332441 is 14423311334041.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 13091913975625 + 951397356816 = 3618275^2 + 975396^2 .

It is a cyclic number.

It is not a de Polignac number, because 14043311332441 - 2²³ = 14043302943833 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 14043311332397 and 14043311332406.

It is not a weakly prime, because it can be changed into another prime (14043311332541) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7021655666220 + 7021655666221.

It is an arithmetic number, because the mean of its divisors is an integer number (7021655666221).

Almost surely, 2^{14043311332441} is an apocalyptic number.

It is an amenable number.

14043311332441 is a deficient number, since it is larger than the sum of its proper divisors (1).

14043311332441 is an equidigital number, since it uses as much as digits as its factorization.

14043311332441 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 41472, while the sum is 34.

Adding to 14043311332441 its reverse (14423311334041), we get a palindrome (28466622666482).

The spelling of 14043311332441 in words is "fourteen trillion, forty-three billion, three hundred eleven million, three hundred thirty-two thousand, four hundred forty-one".