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140434325245013 is a prime number
BaseRepresentation
bin11111111011100101101010…
…000100100000110001010101
3200102020101112120211000200212
4133323211222010200301111
5121401333444230320023
61214402345520215205
741403021331664522
oct3773455204406125
9612211476730625
10140434325245013
1140823954538228
121390114346a505
136048b91531bb7
1426970b4114149
1511380445cce78
hex7fb96a120c55

140434325245013 has 2 divisors, whose sum is σ = 140434325245014. Its totient is φ = 140434325245012.

The previous prime is 140434325245009. The next prime is 140434325245021. The reversal of 140434325245013 is 310542523434041.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 106175569047409 + 34258756197604 = 10304153^2 + 5853098^2 .

It is a cyclic number.

It is not a de Polignac number, because 140434325245013 - 22 = 140434325245009 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (140434325245073) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70217162622506 + 70217162622507.

It is an arithmetic number, because the mean of its divisors is an integer number (70217162622507).

Almost surely, 2140434325245013 is an apocalyptic number.

It is an amenable number.

140434325245013 is a deficient number, since it is larger than the sum of its proper divisors (1).

140434325245013 is an equidigital number, since it uses as much as digits as its factorization.

140434325245013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 691200, while the sum is 41.

Adding to 140434325245013 its reverse (310542523434041), we get a palindrome (450976848679054).

The spelling of 140434325245013 in words is "one hundred forty trillion, four hundred thirty-four billion, three hundred twenty-five million, two hundred forty-five thousand, thirteen".