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140441043133117 is a prime number
BaseRepresentation
bin11111111011101011111010…
…011111001110001010111101
3200102021000212202201002201101
4133323223322133032022331
5121401441224020224432
61214405420300013101
741403346654046236
oct3773537237161275
9612230782632641
10140441043133117
1140826791615a71
12139024b9231191
1360496c226110c
1426975503d608d
1511382d926d4e7
hex7fbafa7ce2bd

140441043133117 has 2 divisors, whose sum is σ = 140441043133118. Its totient is φ = 140441043133116.

The previous prime is 140441043133093. The next prime is 140441043133247. The reversal of 140441043133117 is 711331340144041.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 124642175034276 + 15798868098841 = 11164326^2 + 3974779^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-140441043133117 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (140441043131117) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70220521566558 + 70220521566559.

It is an arithmetic number, because the mean of its divisors is an integer number (70220521566559).

Almost surely, 2140441043133117 is an apocalyptic number.

It is an amenable number.

140441043133117 is a deficient number, since it is larger than the sum of its proper divisors (1).

140441043133117 is an equidigital number, since it uses as much as digits as its factorization.

140441043133117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 48384, while the sum is 37.

Adding to 140441043133117 its reverse (711331340144041), we get a palindrome (851772383277158).

The spelling of 140441043133117 in words is "one hundred forty trillion, four hundred forty-one billion, forty-three million, one hundred thirty-three thousand, one hundred seventeen".