14044113325111 has 2 divisors, whose sum is σ = 14044113325112. Its totient is φ = 14044113325110.

The previous prime is 14044113325049. The next prime is 14044113325129. The reversal of 14044113325111 is 11152331144041.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 14044113325111 - 2³⁹ = 13494357511223 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14044113325141) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7022056662555 + 7022056662556.

It is an arithmetic number, because the mean of its divisors is an integer number (7022056662556).

Almost surely, 2^{14044113325111} is an apocalyptic number.

14044113325111 is a deficient number, since it is larger than the sum of its proper divisors (1).

14044113325111 is an equidigital number, since it uses as much as digits as its factorization.

14044113325111 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5760, while the sum is 31.

Adding to 14044113325111 its reverse (11152331144041), we get a palindrome (25196444469152).

The spelling of 14044113325111 in words is "fourteen trillion, forty-four billion, one hundred thirteen million, three hundred twenty-five thousand, one hundred eleven".