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140444402401421 is a prime number
BaseRepresentation
bin11111111011101111000010…
…101101110100000010001101
3200102021100112212202121111222
4133323233002231310002031
5121402020114003321141
61214411133500453125
741403526134260336
oct3773570255640215
9612240485677458
10140444402401421
1140828155860a68
121390309624a1a5
136049b091c5341
14269778c5dd28d
15113843412c14b
hex7fbbc2b7408d

140444402401421 has 2 divisors, whose sum is σ = 140444402401422. Its totient is φ = 140444402401420.

The previous prime is 140444402401363. The next prime is 140444402401427. The reversal of 140444402401421 is 124104204444041.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 95406693493225 + 45037708908196 = 9767635^2 + 6711014^2 .

It is an emirp because it is prime and its reverse (124104204444041) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 140444402401421 - 210 = 140444402400397 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (140444402401427) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70222201200710 + 70222201200711.

It is an arithmetic number, because the mean of its divisors is an integer number (70222201200711).

Almost surely, 2140444402401421 is an apocalyptic number.

It is an amenable number.

140444402401421 is a deficient number, since it is larger than the sum of its proper divisors (1).

140444402401421 is an equidigital number, since it uses as much as digits as its factorization.

140444402401421 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 65536, while the sum is 35.

Adding to 140444402401421 its reverse (124104204444041), we get a palindrome (264548606845462).

The spelling of 140444402401421 in words is "one hundred forty trillion, four hundred forty-four billion, four hundred two million, four hundred one thousand, four hundred twenty-one".