14044913081 has 2 divisors, whose sum is σ = 14044913082. Its totient is φ = 14044913080.

The previous prime is 14044913053. The next prime is 14044913083. The reversal of 14044913081 is 18031944041.

14044913081 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10456903081 + 3588010000 = 102259^2 + 59900^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-14044913081 is a prime.

It is a super-2 number, since 2×14044913081² (a number of 21 digits) contains 22 as substring.

Together with 14044913083, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (14044913083) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7022456540 + 7022456541.

It is an arithmetic number, because the mean of its divisors is an integer number (7022456541).

Almost surely, 2^14044913081 is an apocalyptic number.

It is an amenable number.

14044913081 is a deficient number, since it is larger than the sum of its proper divisors (1).

14044913081 is an equidigital number, since it uses as much as digits as its factorization.

14044913081 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 13824, while the sum is 35.

The spelling of 14044913081 in words is "fourteen billion, forty-four million, nine hundred thirteen thousand, eighty-one".