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140453414711 is a prime number
BaseRepresentation
bin1000001011001110101…
…1010000011100110111
3111102112102212201210122
42002303223100130313
54300122033232321
6144305020042155
713101365220041
oct2026353203467
9442472781718
10140453414711
1154625322345
122327969335b
13103247b601c
146b25938a91
1539c09368ab
hex20b3ad0737

140453414711 has 2 divisors, whose sum is σ = 140453414712. Its totient is φ = 140453414710.

The previous prime is 140453414617. The next prime is 140453414723. The reversal of 140453414711 is 117414354041.

140453414711 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-140453414711 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (140453411711) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70226707355 + 70226707356.

It is an arithmetic number, because the mean of its divisors is an integer number (70226707356).

Almost surely, 2140453414711 is an apocalyptic number.

140453414711 is a deficient number, since it is larger than the sum of its proper divisors (1).

140453414711 is an equidigital number, since it uses as much as digits as its factorization.

140453414711 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 26880, while the sum is 35.

Adding to 140453414711 its reverse (117414354041), we get a palindrome (257867768752).

The spelling of 140453414711 in words is "one hundred forty billion, four hundred fifty-three million, four hundred fourteen thousand, seven hundred eleven".