Base | Representation |
---|---|
bin | 1000001011001111001… |
… | …0010000110010101001 |
3 | 111102112120100000212112 |
4 | 2002303302100302221 |
5 | 4300123021013423 |
6 | 144305123252105 |
7 | 13101416636012 |
oct | 2026362206251 |
9 | 442476300775 |
10 | 140455251113 |
11 | 54626367031 |
12 | 2327a21a035 |
13 | 10324ca9b58 |
14 | 6b25c96009 |
15 | 39c0b9aa78 |
hex | 20b3c90ca9 |
140455251113 has 2 divisors, whose sum is σ = 140455251114. Its totient is φ = 140455251112.
The previous prime is 140455251073. The next prime is 140455251133. The reversal of 140455251113 is 311152554041.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 134155177984 + 6300073129 = 366272^2 + 79373^2 .
It is a cyclic number.
It is not a de Polignac number, because 140455251113 - 26 = 140455251049 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 140455251113.
It is not a weakly prime, because it can be changed into another prime (140455251133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70227625556 + 70227625557.
It is an arithmetic number, because the mean of its divisors is an integer number (70227625557).
Almost surely, 2140455251113 is an apocalyptic number.
It is an amenable number.
140455251113 is a deficient number, since it is larger than the sum of its proper divisors (1).
140455251113 is an equidigital number, since it uses as much as digits as its factorization.
140455251113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12000, while the sum is 32.
The spelling of 140455251113 in words is "one hundred forty billion, four hundred fifty-five million, two hundred fifty-one thousand, one hundred thirteen".
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