140501540117 has 2 divisors, whose sum is σ = 140501540118. Its totient is φ = 140501540116.

The previous prime is 140501540083. The next prime is 140501540141. The reversal of 140501540117 is 711045105041.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 106324253476 + 34177286641 = 326074^2 + 184871^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-140501540117 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 140501540117.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (140501540147) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70250770058 + 70250770059.

It is an arithmetic number, because the mean of its divisors is an integer number (70250770059).

Almost surely, 2^140501540117 is an apocalyptic number.

It is an amenable number.

140501540117 is a deficient number, since it is larger than the sum of its proper divisors (1).

140501540117 is an equidigital number, since it uses as much as digits as its factorization.

140501540117 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2800, while the sum is 29.

Adding to 140501540117 its reverse (711045105041), we get a palindrome (851546645158).

The spelling of 140501540117 in words is "one hundred forty billion, five hundred one million, five hundred forty thousand, one hundred seventeen".