Base | Representation |
---|---|
bin | 10100011100100011001… |
… | …001101110111111110111 |
3 | 11222022122221021121012111 |
4 | 110130203021232333313 |
5 | 141010012234411101 |
6 | 2553245054231451 |
7 | 203340205312534 |
oct | 24344311567767 |
9 | 4868587247174 |
10 | 1405044060151 |
11 | 4a196a819346 |
12 | 1a83824b5587 |
13 | a2658921354 |
14 | 4c00c499d8b |
15 | 26835dbb251 |
hex | 1472326eff7 |
1405044060151 has 2 divisors, whose sum is σ = 1405044060152. Its totient is φ = 1405044060150.
The previous prime is 1405044060139. The next prime is 1405044060157. The reversal of 1405044060151 is 1510604405041.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1405044060151 - 215 = 1405044027383 is a prime.
It is a super-2 number, since 2×14050440601512 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1405044060157) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 702522030075 + 702522030076.
It is an arithmetic number, because the mean of its divisors is an integer number (702522030076).
Almost surely, 21405044060151 is an apocalyptic number.
1405044060151 is a deficient number, since it is larger than the sum of its proper divisors (1).
1405044060151 is an equidigital number, since it uses as much as digits as its factorization.
1405044060151 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 9600, while the sum is 31.
Adding to 1405044060151 its reverse (1510604405041), we get a palindrome (2915648465192).
The spelling of 1405044060151 in words is "one trillion, four hundred five billion, forty-four million, sixty thousand, one hundred fifty-one".
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