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14050441453 is a prime number
BaseRepresentation
bin11010001010111100…
…01011100011101101
31100021012101101020111
431011132023203231
5212233403111303
610242113420021
71005116532106
oct150536134355
940235341214
1014050441453
115a60120694
12288156a611
13142bbc01a9
149740873ad
15573798b6d
hex34578b8ed

14050441453 has 2 divisors, whose sum is σ = 14050441454. Its totient is φ = 14050441452.

The previous prime is 14050441429. The next prime is 14050441463. The reversal of 14050441453 is 35414405041.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13962494569 + 87946884 = 118163^2 + 9378^2 .

It is a cyclic number.

It is not a de Polignac number, because 14050441453 - 25 = 14050441421 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14050441463) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7025220726 + 7025220727.

It is an arithmetic number, because the mean of its divisors is an integer number (7025220727).

Almost surely, 214050441453 is an apocalyptic number.

It is an amenable number.

14050441453 is a deficient number, since it is larger than the sum of its proper divisors (1).

14050441453 is an equidigital number, since it uses as much as digits as its factorization.

14050441453 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 19200, while the sum is 31.

Adding to 14050441453 its reverse (35414405041), we get a palindrome (49464846494).

The spelling of 14050441453 in words is "fourteen billion, fifty million, four hundred forty-one thousand, four hundred fifty-three".