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14051555047 is a prime number
BaseRepresentation
bin11010001011000100…
…11011011011100111
31100021021110221210201
431011202123123213
5212234144230142
610242153331331
71005132150535
oct150542333347
940237427721
1014051555047
115a60811312
122881a06b47
13142c1c001a
14974297155
15573918ab7
hex34589b6e7

14051555047 has 2 divisors, whose sum is σ = 14051555048. Its totient is φ = 14051555046.

The previous prime is 14051554981. The next prime is 14051555087. The reversal of 14051555047 is 74055515041.

It is a strong prime.

It is an emirp because it is prime and its reverse (74055515041) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14051555047 is a prime.

It is a super-3 number, since 3×140515550473 (a number of 31 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 14051554997 and 14051555015.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14051555087) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7025777523 + 7025777524.

It is an arithmetic number, because the mean of its divisors is an integer number (7025777524).

Almost surely, 214051555047 is an apocalyptic number.

14051555047 is a deficient number, since it is larger than the sum of its proper divisors (1).

14051555047 is an equidigital number, since it uses as much as digits as its factorization.

14051555047 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 70000, while the sum is 37.

The spelling of 14051555047 in words is "fourteen billion, fifty-one million, five hundred fifty-five thousand, forty-seven".