Base | Representation |
---|---|
bin | 1100110001111110011010… |
… | …0001110111000111001111 |
3 | 1211202102111012220222001112 |
4 | 3030133212201313013033 |
5 | 3320214420122131031 |
6 | 45515420204202235 |
7 | 2650163101155665 |
oct | 314374641670717 |
9 | 54672435828045 |
10 | 14052705661391 |
11 | 452879aaa1131 |
12 | 16ab61283937b |
13 | 7ac21a410237 |
14 | 368224266c35 |
15 | 19582309562b |
hex | cc7e68771cf |
14052705661391 has 2 divisors, whose sum is σ = 14052705661392. Its totient is φ = 14052705661390.
The previous prime is 14052705661363. The next prime is 14052705661427. The reversal of 14052705661391 is 19316650725041.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 14052705661391 - 26 = 14052705661327 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14052705661331) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7026352830695 + 7026352830696.
It is an arithmetic number, because the mean of its divisors is an integer number (7026352830696).
Almost surely, 214052705661391 is an apocalyptic number.
14052705661391 is a deficient number, since it is larger than the sum of its proper divisors (1).
14052705661391 is an equidigital number, since it uses as much as digits as its factorization.
14052705661391 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1360800, while the sum is 50.
The spelling of 14052705661391 in words is "fourteen trillion, fifty-two billion, seven hundred five million, six hundred sixty-one thousand, three hundred ninety-one".
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