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14053103510342 = 2131999612703047
BaseRepresentation
bin1100110001111111111000…
…1111100010001101000110
31211202110111221112210012212
43030133332033202031012
53320221223444312332
645515523455343422
72650206001631321
oct314377617421506
954673457483185
1014053103510342
114528984627a16
1216ab703b21b72
137ac28197a710
1436826102b7b8
15195847e818b2
hexcc7fe3e2346

14053103510342 has 16 divisors (see below), whose sum is σ = 22701289135392. Its totient is φ = 6486012937920.

The previous prime is 14053103510231. The next prime is 14053103510371. The reversal of 14053103510342 is 24301530135041.

It is a super-3 number, since 3×140531035103423 (a number of 40 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 14053103510299 and 14053103510308.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3847463 + ... + 6550509.

It is an arithmetic number, because the mean of its divisors is an integer number (1418830570962).

Almost surely, 214053103510342 is an apocalyptic number.

14053103510342 is a deficient number, since it is larger than the sum of its proper divisors (8648185625050).

14053103510342 is a wasteful number, since it uses less digits than its factorization.

14053103510342 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2903023.

The product of its (nonzero) digits is 21600, while the sum is 32.

Adding to 14053103510342 its reverse (24301530135041), we get a palindrome (38354633645383).

The spelling of 14053103510342 in words is "fourteen trillion, fifty-three billion, one hundred three million, five hundred ten thousand, three hundred forty-two".

Divisors: 1 2 13 26 199961 399922 2599493 2703047 5198986 5406094 35139611 70279222 540503981167 1081007962334 7026551755171 14053103510342