Base | Representation |
---|---|
bin | 1100110010000000000010… |
… | …0100011000101111100111 |
3 | 1211202110121122222020120011 |
4 | 3030200000210120233213 |
5 | 3320221313441443142 |
6 | 45515531411551051 |
7 | 2650206654410314 |
oct | 314400044305747 |
9 | 54673548866504 |
10 | 14053142531047 |
11 | 45289a4659834 |
12 | 16ab714bbb487 |
13 | 7ac289a905a9 |
14 | 3682662a7d0b |
15 | 19584b5dd417 |
hex | cc800918be7 |
14053142531047 has 2 divisors, whose sum is σ = 14053142531048. Its totient is φ = 14053142531046.
The previous prime is 14053142531003. The next prime is 14053142531093. The reversal of 14053142531047 is 74013524135041.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14053142531047 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14053122531047) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7026571265523 + 7026571265524.
It is an arithmetic number, because the mean of its divisors is an integer number (7026571265524).
Almost surely, 214053142531047 is an apocalyptic number.
14053142531047 is a deficient number, since it is larger than the sum of its proper divisors (1).
14053142531047 is an equidigital number, since it uses as much as digits as its factorization.
14053142531047 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 201600, while the sum is 40.
Adding to 14053142531047 its reverse (74013524135041), we get a palindrome (88066666666088).
The spelling of 14053142531047 in words is "fourteen trillion, fifty-three billion, one hundred forty-two million, five hundred thirty-one thousand, forty-seven".
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