Base | Representation |
---|---|
bin | 11010001011010010… |
… | …00101101110011011 |
3 | 1100021101202200000002 |
4 | 31011221011232123 |
5 | 212240121114042 |
6 | 10242255003215 |
7 | 1005153042314 |
oct | 150551055633 |
9 | 40241680002 |
10 | 14053301147 |
11 | 5a617a4176 |
12 | 288250950b |
13 | 142c681a12 |
14 | 9745cd60b |
15 | 573b61132 |
hex | 345a45b9b |
14053301147 has 2 divisors, whose sum is σ = 14053301148. Its totient is φ = 14053301146.
The previous prime is 14053301117. The next prime is 14053301159. The reversal of 14053301147 is 74110335041.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 14053301147 - 212 = 14053297051 is a prime.
It is not a weakly prime, because it can be changed into another prime (14053301117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7026650573 + 7026650574.
It is an arithmetic number, because the mean of its divisors is an integer number (7026650574).
Almost surely, 214053301147 is an apocalyptic number.
14053301147 is a deficient number, since it is larger than the sum of its proper divisors (1).
14053301147 is an equidigital number, since it uses as much as digits as its factorization.
14053301147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5040, while the sum is 29.
Adding to 14053301147 its reverse (74110335041), we get a palindrome (88163636188).
The spelling of 14053301147 in words is "fourteen billion, fifty-three million, three hundred one thousand, one hundred forty-seven".
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