Search a number
-
+
14053301117 is a prime number
BaseRepresentation
bin11010001011010010…
…00101101101111101
31100021101202122221222
431011221011231331
5212240121113432
610242255003125
71005153042242
oct150551055575
940241678858
1014053301117
115a617a4149
1228825094a5
13142c6819bb
149745cd5c9
15573b61112
hex345a45b7d

14053301117 has 2 divisors, whose sum is σ = 14053301118. Its totient is φ = 14053301116.

The previous prime is 14053301089. The next prime is 14053301147. The reversal of 14053301117 is 71110335041.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 13826467396 + 226833721 = 117586^2 + 15061^2 .

It is a cyclic number.

It is not a de Polignac number, because 14053301117 - 28 = 14053300861 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14053301147) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7026650558 + 7026650559.

It is an arithmetic number, because the mean of its divisors is an integer number (7026650559).

Almost surely, 214053301117 is an apocalyptic number.

It is an amenable number.

14053301117 is a deficient number, since it is larger than the sum of its proper divisors (1).

14053301117 is an equidigital number, since it uses as much as digits as its factorization.

14053301117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1260, while the sum is 26.

Adding to 14053301117 its reverse (71110335041), we get a palindrome (85163636158).

The spelling of 14053301117 in words is "fourteen billion, fifty-three million, three hundred one thousand, one hundred seventeen".