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14055255521 is a prime number
BaseRepresentation
bin11010001011100001…
…00010110111100001
31100021112102221220022
431011300202313201
5212241121134041
610242404523225
71005205462226
oct150560426741
940245387808
1014055255521
115a6290955a
1228830b0515
13142cbb7458
1497497b94d
15573dea24b
hex345c22de1

14055255521 has 2 divisors, whose sum is σ = 14055255522. Its totient is φ = 14055255520.

The previous prime is 14055255517. The next prime is 14055255523. The reversal of 14055255521 is 12555255041.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10300017121 + 3755238400 = 101489^2 + 61280^2 .

It is a cyclic number.

It is not a de Polignac number, because 14055255521 - 22 = 14055255517 is a prime.

Together with 14055255523, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (14055255523) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7027627760 + 7027627761.

It is an arithmetic number, because the mean of its divisors is an integer number (7027627761).

Almost surely, 214055255521 is an apocalyptic number.

It is an amenable number.

14055255521 is a deficient number, since it is larger than the sum of its proper divisors (1).

14055255521 is an equidigital number, since it uses as much as digits as its factorization.

14055255521 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 50000, while the sum is 35.

The spelling of 14055255521 in words is "fourteen billion, fifty-five million, two hundred fifty-five thousand, five hundred twenty-one".