Base | Representation |
---|---|
bin | 1000001011100110100… |
… | …1010000010101011111 |
3 | 111102210102022022001022 |
4 | 2002321221100111133 |
5 | 4300323202200442 |
6 | 144322554234355 |
7 | 13104022330112 |
oct | 2027151202537 |
9 | 442712268038 |
10 | 140553553247 |
11 | 546768a8968 |
12 | 232a71259bb |
13 | 1033c4778b3 |
14 | 6b34d64579 |
15 | 39c96173d2 |
hex | 20b9a5055f |
140553553247 has 2 divisors, whose sum is σ = 140553553248. Its totient is φ = 140553553246.
The previous prime is 140553553171. The next prime is 140553553253. The reversal of 140553553247 is 742355355041.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 140553553247 - 220 = 140552504671 is a prime.
It is a super-3 number, since 3×1405535532473 (a number of 34 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 140553553198 and 140553553207.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (140553553277) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70276776623 + 70276776624.
It is an arithmetic number, because the mean of its divisors is an integer number (70276776624).
Almost surely, 2140553553247 is an apocalyptic number.
140553553247 is a deficient number, since it is larger than the sum of its proper divisors (1).
140553553247 is an equidigital number, since it uses as much as digits as its factorization.
140553553247 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1260000, while the sum is 44.
The spelling of 140553553247 in words is "one hundred forty billion, five hundred fifty-three million, five hundred fifty-three thousand, two hundred forty-seven".
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