1406036501131 has 2 divisors, whose sum is σ = 1406036501132. Its totient is φ = 1406036501130.

The previous prime is 1406036501099. The next prime is 1406036501153. The reversal of 1406036501131 is 1311056306041.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1406036501131 - 2⁵ = 1406036501099 is a prime.

It is a super-2 number, since 2×1406036501131² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1406036501093 and 1406036501102.

It is not a weakly prime, because it can be changed into another prime (1406036501161) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 703018250565 + 703018250566.

It is an arithmetic number, because the mean of its divisors is an integer number (703018250566).

Almost surely, 2^{1406036501131} is an apocalyptic number.

1406036501131 is a deficient number, since it is larger than the sum of its proper divisors (1).

1406036501131 is an equidigital number, since it uses as much as digits as its factorization.

1406036501131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6480, while the sum is 31.

The spelling of 1406036501131 in words is "one trillion, four hundred six billion, thirty-six million, five hundred one thousand, one hundred thirty-one".