Search a number
-
+
14061262211153 is a prime number
BaseRepresentation
bin1100110010011110010010…
…0010100000100001010001
31211210020120112120201200222
43030213210202200201101
53320334431111224103
645523353224522425
72650615120510133
oct314474442404121
954706515521628
1014061262211153
114531390a3a663
1216b1200320415
137acc82047b31
143687d6807053
15195b74379638
hexcc9e48a0851

14061262211153 has 2 divisors, whose sum is σ = 14061262211154. Its totient is φ = 14061262211152.

The previous prime is 14061262211077. The next prime is 14061262211189. The reversal of 14061262211153 is 35111226216041.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12580591829569 + 1480670381584 = 3546913^2 + 1216828^2 .

It is a cyclic number.

It is not a de Polignac number, because 14061262211153 - 214 = 14061262194769 is a prime.

It is not a weakly prime, because it can be changed into another prime (14061262211053) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7030631105576 + 7030631105577.

It is an arithmetic number, because the mean of its divisors is an integer number (7030631105577).

Almost surely, 214061262211153 is an apocalyptic number.

It is an amenable number.

14061262211153 is a deficient number, since it is larger than the sum of its proper divisors (1).

14061262211153 is an equidigital number, since it uses as much as digits as its factorization.

14061262211153 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 17280, while the sum is 35.

Adding to 14061262211153 its reverse (35111226216041), we get a palindrome (49172488427194).

The spelling of 14061262211153 in words is "fourteen trillion, sixty-one billion, two hundred sixty-two million, two hundred eleven thousand, one hundred fifty-three".