Base | Representation |
---|---|
bin | 1100110010100110100000… |
… | …1101010101010110001111 |
3 | 1211210110021111021200021012 |
4 | 3030221220031111112033 |
5 | 3320403442120043004 |
6 | 45524400340155435 |
7 | 2651023633165046 |
oct | 314515015252617 |
9 | 54713244250235 |
10 | 14063471252879 |
11 | 4532314985384 |
12 | 16b1718098b7b |
13 | 7b02448c3b09 |
14 | 368965d5955d |
15 | 195c5328046e |
hex | cca6835558f |
14063471252879 has 2 divisors, whose sum is σ = 14063471252880. Its totient is φ = 14063471252878.
The previous prime is 14063471252827. The next prime is 14063471252921. The reversal of 14063471252879 is 97825217436041.
14063471252879 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14063471252879 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14063471252179) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7031735626439 + 7031735626440.
It is an arithmetic number, because the mean of its divisors is an integer number (7031735626440).
It is a 1-persistent number, because it is pandigital, but 2⋅14063471252879 = 28126942505758 is not.
Almost surely, 214063471252879 is an apocalyptic number.
14063471252879 is a deficient number, since it is larger than the sum of its proper divisors (1).
14063471252879 is an equidigital number, since it uses as much as digits as its factorization.
14063471252879 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 20321280, while the sum is 59.
The spelling of 14063471252879 in words is "fourteen trillion, sixty-three billion, four hundred seventy-one million, two hundred fifty-two thousand, eight hundred seventy-nine".
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