Base | Representation |
---|---|
bin | 101001111011010… |
… | …0100010011110111 |
3 | 10122001011112020011 |
4 | 1103312210103313 |
5 | 10340121012211 |
6 | 351332521051 |
7 | 46601500612 |
oct | 12366442367 |
9 | 3561145204 |
10 | 1406813431 |
11 | 662122831 |
12 | 333180187 |
13 | 1955c5aaa |
14 | d4ba7179 |
15 | 8378d921 |
hex | 53da44f7 |
1406813431 has 2 divisors, whose sum is σ = 1406813432. Its totient is φ = 1406813430.
The previous prime is 1406813411. The next prime is 1406813453. The reversal of 1406813431 is 1343186041.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1406813431 - 221 = 1404716279 is a prime.
It is a super-2 number, since 2×14068134312 = 3958248059283983522, which contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1406813393 and 1406813402.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1406813411) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 703406715 + 703406716.
It is an arithmetic number, because the mean of its divisors is an integer number (703406716).
Almost surely, 21406813431 is an apocalyptic number.
1406813431 is a deficient number, since it is larger than the sum of its proper divisors (1).
1406813431 is an equidigital number, since it uses as much as digits as its factorization.
1406813431 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6912, while the sum is 31.
The square root of 1406813431 is about 37507.5116609993. The cubic root of 1406813431 is about 1120.5007940594.
Adding to 1406813431 its reverse (1343186041), we get a palindrome (2749999472).
The spelling of 1406813431 in words is "one billion, four hundred six million, eight hundred thirteen thousand, four hundred thirty-one".
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